If a + b + c = 9 and ab + bc + ca = 20 then find a^2 + b^2 + c^2
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Step-by-step explanation:
a+b+c=9 given
squaring both side
= (a + b + c)^2=(9)^2
= a^2+b^2 +c^2 2ab+2bc+2ca=81
a^2+b^2+c^2=2(ab+bc+ca)=81
a^2+b^2+c^2=2×20=81
a^2+b^2+c^2=81-40=61 @nswer by yadav Bajrangi
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