If a+b+c=9 and ab+bc+ca=23, find the value of a2+b2+c2
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Answered by
4
(a+b+C)^2=a^2+b^2+c^2+2(ab+bc+ca)
9^2=a^2+b^2+c^2+2×23
81=a^2+b^2+c^2+46
81-46=a^2+b^2+c^2
35=a^2+b^2+c^2(answer)
9^2=a^2+b^2+c^2+2×23
81=a^2+b^2+c^2+46
81-46=a^2+b^2+c^2
35=a^2+b^2+c^2(answer)
Answered by
8
(a+b+c)^2= (9)^2 =81
a^2+b^2+c^2+2×23 =81
a^2+b^2+c^2=81-46
a^2+b^2+c^2 = 35
HOPE IT HELPS YOU
HAVE SWEET DREAMS.
a^2+b^2+c^2+2×23 =81
a^2+b^2+c^2=81-46
a^2+b^2+c^2 = 35
HOPE IT HELPS YOU
HAVE SWEET DREAMS.
pranjaldhote:
I don't know that's why I asked you no..!!
Ohhk sorry
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