Question

If a+b+c = 9 and ab+bc+ca = 23 , find the value of a3+b3+c3 -3abc. plss help​

Answer 1

Answer:

108

Explanation:

a+b+c=9

squaring both sides

(a+b+c)^2=9^2

a2+b2+c2+2(ab+bc+ca)=81

a2+b2+c2+2(23)=81

a2+b2+c2+(46)=81

a2+b2+c2=81-46

a2+b2+c2=35

a3-b3-c3-3abc

(a+b+c)(a2+b2+c2-ab-bc-ca)

9×12(35-23)

108

Hope it Helps..