if a+b+c =9 and ab+bc+ca =26, find a²+b²+c².
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Answered by
1
Answer:
29
Step-by-step explanation:
a²+b²+c²
=(a+b+c)²-2ab-2bc-2ca [(a²+b²)=(a+b)²-2ab]
=(a+b+c)²-2(ab+bc+ca)
=9²-2×26 [a+b+c=9; ab+bc+ca=26]
=81-52
=29
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