Question

If a+b+c=9 and ab+bc+ca = 26 find a2 + b2 + c2 and a3 + b3 + c3 – 3abc

Answer 1

Answer:

a² + b² + c² = 29 and a³ + b³ + c³ - 3abc = 27

Step-by-step explanation:

a + b + c = 9

ab + bc + ac = 26

Find a² + b² + c² and a³ + b³ + c³ - 3abc

We know , (a + b + c)² = a² + b² + c² + 2(ab + bc + ac)

9² = a² + b² + c² + 2(26)

a² + b² + c² = 81 - 52

a² + b² + c² = 29

We know , (a + b + c)³ - 3abc = (a + b + c)(a² + b² + c² - ab - bc - ac)

= 9 ( 29 - 26)

= 9 x 3

= 27

Hope you get it...