if a+b+c=9 and ab+bc+ca=26,find the value of a square +b sqauare +c square
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6
a+b+c =9
ab +bc + ca =26
a^2+ b^2+c^2= ?
(a+b+c)^3 =a square +b square +c square +2 (ab +bc + ca)
(9)^2=a^2+b^2+c^2+2(26)
81=a^2+b^2+c^2+52
81-52 =a^2+b^2+c^2
29 is the answer
ab +bc + ca =26
a^2+ b^2+c^2= ?
(a+b+c)^3 =a square +b square +c square +2 (ab +bc + ca)
(9)^2=a^2+b^2+c^2+2(26)
81=a^2+b^2+c^2+52
81-52 =a^2+b^2+c^2
29 is the answer
3jassi:
ok
welcome
my answer is correct
i corret the Answer
no its not correct
you see
Answered by
6
a+b+c=9
ab+bc+ca=26
(a+b+c)^2=a^2 +b^2+c^2+2(ab+bc+ca)
(9)^2 =a^2+b^2+c^2+2(26)
81=a^2+b^2+c^2+52
81-52=a^2+b^2+c^2
29 =a^2+b^2+c^2
ab+bc+ca=26
(a+b+c)^2=a^2 +b^2+c^2+2(ab+bc+ca)
(9)^2 =a^2+b^2+c^2+2(26)
81=a^2+b^2+c^2+52
81-52=a^2+b^2+c^2
29 =a^2+b^2+c^2
oh bro 2 (26) =56 or 52
52
but you have written as 56
oop i didi wrong sorry
it's okay but say to him that you are worng
yes now its correct
ok
thank you for telling me
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