Question

If a + b + c = 9 and ab + bc + ca = 26, then find a^2 + b^2+ c^2?​

Answer 1

Answer:

$a + b + c = 9$

${(a + b + c)}^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2(ab + bc + ca)$

${9}^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2(26)$

${a}^{2} + {b}^{2} + {c}^{2} = 81 - 52$

${a}^{2} + {b}^{2} + {c}^{2} =29$

Answer 2

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