Question

If a+b+c=9 and ab+bc+ca=26 , then find (a raise to power 2 ) + ( b raise to power 2) + (c raise to power 2)​

Answer 1

Answer:

(a raise to power) + (b raise to power 2) + (c raise to power 2) = 29.

Step-by-step explanation:

a + b + c = 9 ,  ab + bc + ca = 26

Now,   $(a+b+c)^{2}$ = $a^{2} +b^{2} +c^{2}$ + 2ab + 2bc + 2ca

       ⇒ $(a+b+c)^{2}$ - 2(ab + bc + ca) = $a^{2} +b^{2} +c^{2}$

       ⇒ $9^{2}$ - 2×26 = $a^{2} +b^{2} +c^{2}$

       ⇒ $a^{2} +b^{2} +c^{2}$ = 81 - 52 = 29