If a+b+c=9 and ab+bc+ca=26 then find a²+b²+c²
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Answer:
Using formula.
a²+b²+c²+2ab+2bc+2ca =(a+b+c) ²
Step-by-step explanation:
Using above equation
And susbitute all given values
a²+b²+c²+2ab+2bc+2ca =(a+b+c) ²
We have to find a²+b²+c², so take 2ab+2bc+2ca to the other side with like.
a²+b²+c²= (a+b+c)² - 2(ab +bc + ca) eq1
Now putting values on eq 1
a²+b²+c²= (9)² + 2(26)
= (81) + (52)
= 133
So a²+b²+c²= 133
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