Question

If a+b+c=9 and ab+bc+CA=26,then find a²+b²±c²​

Answer 1

Answer:

29

Step-by-step explanation:

a + b + c = 9

ab + bc + ca = 26

(a + b + c)^2 = a^2 + b^2 + c^2 +2(ab + bc + ca)

therefore ,

9^2 = a2 + b2+ c2 + 2(26)

81 = 52 + a²+b²±c²​

a²+b²±c²​ = 81 - 52

a²+b²±c²​ = 29

Answer 2

Question:

If a + b + c = 9 and ab + bc + ca = 26,then find a² + b² + c²​

Answer:

a² + b² + c² = 61

Step-by-step explanation:

Given =>

a + b + c = 9            

ab + bc + ca = 26

To find =>

a² + b² + c²

By using the identity

a² + b² + c² = a +b +c + 2ab + 2bc + 2ca

                  = 9 + 2(26) (taking 2 as common)

                  = 9 + 52

a² + b² + c² = 61

Hope you understand.