Question

IF a+b+c=9
and
ab+bc+ca=26


then find the value of a^+b^2+c^2.​

Answer 1

Answer:

29 is the answer

Step-by-step explanation:

given

a+b+c=9,  ab+bc+ca=26

so if we square a+b+cu get (a+b+c)^2 = a^2+b^2+c^2+2(ab+bc+ca )

you can see that there are two given values i.e. a+b +c,ab+bc+ca if you substitute with the values you will get like this :

(a+b+c)^2 is equal to 81 and 2(ab+bc+ca)= 52 and if you put this values in the equation you will get something like this:81=a^2+b^2+c^2+52 and if you bring the 52 to the other side of the equation you will get something like this:

81-52=a^2+b^2+c^2 and if you substitute you will get a^2+b^2+c^2 =29

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hope it is helpful

Karthikeya

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