if a+b+c=9 and ab+bc+ca= 40 find a^2
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(a+b+c)^2 = 9^2
a^2 + b^2 + c^2 +2ab +2bc +2ca = 81
a^2 + b^2 + c^2 + 2( ab + bc+ ca ) = 81
a^2 + b^2 + c^2 + 2×40 = 81
a^2 + b^2 + c^2 + 80 = 81
a^2 + b^2 + c^2 = 81 - 80
a^2 + b^2 + c^2 = 1
hope it helps.!!
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