If a+b+c=9 and ab+bc+ca=40,find a^2+b^2+c^2
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Answered by
5
(a+b+c)^2= a^2+b^2+c^2+2ab+2bc+2ca
(9)^2 =a2+b+2+c2+2(ab+bc+ca)
81-80=a2+b2+c2
1 is the answer
(9)^2 =a2+b+2+c2+2(ab+bc+ca)
81-80=a2+b2+c2
1 is the answer
Answered by
6
We Know that....
(a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca
so by putting the values...
9^2=a^2+b^2+c^2+40
or ...
a^2+b^2+c^2=81-40
=41
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