If a + b + C = 9 and ab +bc+ca = 40 then find the value of a^3+b^3+c^3-3abc
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utkarshkumarsipcbezi:
simplify (a^2-b^2)+(b^2-c^2)+(c^2-a^2)/(a-b)^3+(b-c)^3+(c-a)^3
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We Know that....
(a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca
so by putting the values...
9^2=a^2+b^2+c^2+40
or ...
a^2+b^2+c^2=81-40
=41
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