If a+b+c=9 and ab+BC+can=26 find a2+ b2+c2
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1
Answer:
29
Step-by-step explanation:
formula is
(a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca
(a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ca)
that means substitute a+b+c=9,
ab+bc+ca=26
then a^2+b^2+c^2=?
(a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ca)
(9)^2=a^2+b^2+c^2+2(26)
81=a^2+b^2+c^2+52
81-52=a^2+b^2+c^2
a^2+b^2+c^=29
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