if a+ b + c= 9 and ab+ca+bc=90
find the value of
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a + b + c = 9
Square on both sides,
(a + b + c)² = a² + b² + c² + 2(ab + bc + ca)
9² = a² + b² + c² + 2(90)
81 = a² + b² + c² + 180
81 - 180 = a² + b² + c²
-99 = a² + b² + c²
Square on both sides,
(a + b + c)² = a² + b² + c² + 2(ab + bc + ca)
9² = a² + b² + c² + 2(90)
81 = a² + b² + c² + 180
81 - 180 = a² + b² + c²
-99 = a² + b² + c²
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