if a+B+C=9 and abb+bc+ca=23 than a^3+b^3+c^3+3abc=
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108
*explanation*
(a+b+c)^2 = (a^2+b2+c2 + 2ab+2bc+2ca)
9^2= a2+b2+c2+ 2(ab+bc+ca)
81 = a2+b2+c2 + 46
a2+b2+c2 = 35
(a+b+c) (a^2+b^2+c^2-ab-bc-ca)
(9) (35-(23))
(9) (12)
108 ans.
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Answer:
that I know...
but how here 6 came...?
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