Question

If a + b + c = 9 and BC + AC + ab = 23 find the value of a square + b square + c square

Answer 1

heya

we know that a² +b² + c² = (a+b+c)² -2(ab +bc +ac)

so a² + b² + c² = (9)² -2(23)

=> a²+b²+c² = 81- 46

=> a² +b²+c² = 35

hope it helps u

#puja

#bebrainly

Answer 2

Answer:

35

Step-by-step explanation:

a+b+c=9, ab+bc+ca=23.

Since we know that: (here, ^ means to the power of and  a^2+b^2+c^2 means a square + b square + c square)

  (a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ca)

⇒(9)^2=a^2+b^2+c^2+2(23)        {(substituting a+b+c =9 and ab+bc+ca=23)}

⇒81=a^2+b^2+c^2+46                 {(9^2 = 81 and 2(23) = 46)}

⇒a^2+b^2+c^2+46=81

⇒a^2+b^2+c^2=35                       {(81-46 = 35)}

So a square + b square + c square= 35.

HOPE IT HELPS.