Question

if a+b+c=9 then 2ab+2bc+2ca=26 then find araise to 2 +b raise to 2 +c raiace to 2​

Answer 1

$Answer : 55$

Given:

• a+b+c=9
• 2(ab+bc+ca)=26

To find:

• $a^2+ b^2+c^2=$

Step-by-step explanation:

${(a + b + c)}^{2} - 2(ab + bc + ca) = {a}^{2} + {b}^{2} + {c}^{2}$

$\rightrightarrows {9}^{2} - 26 = {a}^{2} + {b}^{2} + {c}^{2}$

$\rightrightarrows55 = {a}^{2} + {b}^{2} + {c}^{2}$

Hence answer= 55