Question

if a+b+c=9 then 2ab+2bc+2ca=26 then find araise to 2 +b raise to 2 +c raiace to 2 plz help me ​

Answer 1

Answer:

$\sf \: 2ab + 2bc + 2ca = 2(ab + bc + ca) \\ \\ \sf (a + b + c)^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2(ab + bc + ca) \\ \\ \sf ( {9})^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2 \times 26 \\ \\ \sf \: {a}^{2} + {b}^{2} + {c}^{2} = 81 - 52 = 29$