if A+B+C=90 then sin 2B+sin 2c=
bigansingh:
Sorry bro that's A+B+C=180 then it's going to be solved
Sry it's right
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A+B+C=90
B+C=90-A
SinB+C=90-A
SinB+SinC=Sin90-A
SinB+Sinc=Sin90/2-A/2
SinB+SinC=Sin45-A/2
SinB+SinC=1/root2-A/2
SinB+SinC=2-Aroot2/2root2
Then Rationalise RHS . After rationalisation you will get the answer that is :-
Root2-4A/2
B+C=90-A
SinB+C=90-A
SinB+SinC=Sin90-A
SinB+Sinc=Sin90/2-A/2
SinB+SinC=Sin45-A/2
SinB+SinC=1/root2-A/2
SinB+SinC=2-Aroot2/2root2
Then Rationalise RHS . After rationalisation you will get the answer that is :-
Root2-4A/2
Hope this may help you
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