if A+B+C=90° then prove that sinA+sinB+sinC=1+4(sin(90-2A)/4)(sin(90-2B)/4)(sin(90-2C)/4)
Answers
Answered by
0
Step-by-step explanation:
itszulusltluzfyoraupatsitljxvuffkyirsyrwiilyfjjsfhchkhczyuraotukjv
Similar questions