If A + B + C = 90°, then sin 2A + sin 2B + sin 2C =
a) cos A. cos B. cos C
b) 2 cos A. cos B. cos C
c) 3 cos A. cos B. cos C
d) 4 cos A. cos B. cos C
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Answer:
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Answer:
d) 4 cos a cos b cos c
Step-by-step explanation:
applying the formula of,
sin c + sin d = 2 sin ( c + d ) /2 • cos ( c - d ) /2
after modifying the math,
cos ( a+b) + cos ( a - b ) = 2 cos a cos b
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