If A + B + C = 90°, then sin 2A + sin 2B + sin 2C =
a) cos A. cos B. cos C
b) 2 cos A. cos B. cos C
c) 3 cos A. cos B. cos C
d) 4 cos A. cos B. cos C
Answers
Answered by
0
Answer:
answer is d
Step-by-step explanation:
sin2a+sin2b+sin2c =4cos i think
Similar questions