if a+b-c/a+b=b+c-a/b+c=c+a-b/c+a and a+b+c=o then
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Answered by
2
a+b+c=0
then, -a=b+c and -b=a+c and -c=a+b therefore
L.H.S
(a+b-c)/a+b
(a+b+a+b)/a+b
2(a+b)/(a+b)
2
same in M.H.S. AND R.H.S.
Proved
then, -a=b+c and -b=a+c and -c=a+b therefore
L.H.S
(a+b-c)/a+b
(a+b+a+b)/a+b
2(a+b)/(a+b)
2
same in M.H.S. AND R.H.S.
Proved
Panks926:
what is relation between a b and c
Answered by
0
Answer: here is your answer
Step-by-step explanation:
a+b+c=0
then, -a=b+c and -b=a+c and -c=a+b therefore
L.H.S
(a+b-c)/a+b
(a+b+a+b)/a+b
2(a+b)/(a+b)
2
same in M.H.S. AND R.H.S.
Proved
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