If (a + b + c) (a - b + c)= a² + b + c² show
that ab, c are in continued proportion
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Step-by-step explanation:
(a + b + c) (a - b + c)= a² + b² + c²
a²-ab+ca+ab-b²+bc+ca-bc+c²=a² + b² + c²
2ca-2b²=0
2b²=2ca
b²=ca
so a/b = b/c
or a:b :: b:c
Thus a,b, c are in continued proportion
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