If a+b+c=abc prove that (1+a²)=(1-ab)(1-ac)
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Answer:
Step-by-step explanation:
Given: a+b+c = abc
To Prove: (1 +a^2) = (1-ab)(1-ac)
Proof:
Considering R.H.S. ,
= (1 - ab)(1 - ac)
= (1 - ab - ac + a*abc)
= (1 - a[b+c] + a[a + b +c])
= (1 - ab -ac + a^2 + ab +ac)
= (1 + a^2)
= L.H.S.
Hence Proved
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