Question

If a!+b!+c!=abc; where a;bandc are distinct decimal digits; find b

Answer 1

jaadhjjejnsjijdjejjshdhjhdh

Answer 2

Answer:4

Step-by-step explanation:

a, b, c cannot be equal to 7,8,9 as their factorials are 4 digits.

a, b, c cannot be equal to 6 as 6!=720 and

We know 'a' not equal to 7,8,9

But if we use 6! 'a' will be 7,8,9.

4!+4!+4!=72

But 72 is two digit.

Therefore we have to use at least one 5 ,

ie a or b or c =5

a, b, c are distinct so largest sum

=5! + 4! +3! = 150

Therefore a=1

The number is

15c or 1b5

If we take all combinations of 15c,

1!+ 5! +4! not equal to 154

1! +5! +3! not equal to 153

1! +5! +2! not equal to 152

If we take 1b5,

1! + 4! +5! = 145

Therefore b= 4