If A+B=C and A^2+B^2=C^2, then prove that A and B are perpendicular to each other?
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Answered by
1
Given that
vector a + vector b = vector c
Which means
C^2 = A^2 + B^2 + 2 A B cosx
Where x is the angle between vector a & vector b
But it is given that
A^2+B^2= C^2
Thus
C^2 = C^2 + 2 A B cosx
2A B cosx = 0
A &B are not zero therefore
Cosx = 0
X = 90 degree
i hope it will help u
Answered by
2
Answer:
Given that
vector a + vector b = vector c
Which means
C^2 = A^2 + B^2 + 2 A B cosx
Where x is the angle between vector a & vector b
But it is given that
A^2+B^2= C^2
Thus
C^2 = C^2 + 2 A B cosx
2A B cosx = 0
A &B are not zero therefore
Cosx = 0
X = 90 degree
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