Question

If a; b; c and d are consecutive natural numbers and a^3=b^3+c^3+d^3,what is the least value of 'a'? PLEASE ANWER FAST

Answer 1

Answer:

The answer is 6,5,4,3

a=6

b=5

c=4

d=3

${a}^{3} = {b}^{3} + {c}^{3} + {d}^{3} \\ 216 = 125 + 64 + 27$