Math, asked by moumita18, 1 year ago

if a b c and d are four consecutive multiples of 8 and A is smaller thanB, B is smaller than C, C is smaller than D then what is the value of (a-c)(d-b)?

Answers

Answered by somra
4
answer is -256
let a=16
b = 24
c = 32
d =40
According to the question
(a-c)(d-b)
put the values
(16-32)(40-24)
=(-16)(16)
=(-256)
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