if a b c and d are four odd perfect cube numbers then which of the following is always a factor of (a⅓+b⅓)^2.(c⅓+d⅓)
divyabillaiya:
Trll me the solutipn
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Thank you for asking this question. Here is your answer:
a = 1
b = 8
c = 125
d = 343
These are the four odd perfect cube numbers
∛a=∛1=1,∛b=∛8=2,∛c=∛125=5 and ∛d=∛343=7
(∛a+∛b)^2 (∛c ∛d) will be 192, 360, 512, 576 and 600
(192, 360, 512, 576, 600) = 8
So this means that 8 will always be the factor of (∛a+∛b)^2 (∛c+∛d)
If there is any confusion please leave a comment below.
Instead of deleting my answer if the question was written in right way , I would have answered correctly.
If you will look at the your answer ,b=27,=3^3,then 16.12= factor 0f 1,2,4,8..
I think you Know the answer before a question is written, that's why your answer is always correct, but not the way to reach at the answer.
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