If a, b, c and d are in continued proportion then prove that
(b + c) + (c - a)2+ (b - d)2 = (a - d)?
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a,b,c,d are in continued proportion
⇒ba=cb=dc=k⇒a=bk,b=ck,c=dk,
To prove a2+b2+c2)(b2+c2+d2)=(ab+bc+cd+)2
substituting a,b,c
⇒((bk)2+(ck)2+(dk)2)(b2+c2+d2)=(b2k+c2k+d2k)2⇒k2(b2+c2+d2)(b2+c2+d2)=k2(b2+c
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