Question

If a, b, c and d are in proportion then prove that (ma+nb):b=(mc+nd):d.

Answer 1

Step-by-step explanation:

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Answer 2

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Since a, b, c, d are in proportion so,

a/b = c/d

da=bc

da-bc=0

m(da-bc)=0

m(da-bc)=n(0)

m(da-bc)=n(bd-db)

dma-bmc=bnd-dnb

dma+dnb=bmc+bnd

d(ma+nb)=b(mc+nd)

(ma+nb)/b = (mc+nd)/d. HENCE PROVED........

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