IF A,B,C and D are whole number such that A plus B =8 , B plus C = 11 , B plus D =13 and C plus D =14 find the value of A,B,C and D
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Answered by
0
Answer:
72
Given that
ab−2(a+b)⇒
a
1
+
b
1
=
2
1
bc=3(b+c)⇒
b
1
+
c
1
=
3
1
ca=4(c+a)⇒
c
1
+
a
1
=
4
1
(
c
1
+
a
1
)−(
a
1
+
b
1
)=
3
1
−
2
1
c
1
−
a
1
=
6
−1
c
1
+
a
1
+
c
1
−
a
1
=
4
1
−
6
1
c
2
=
12
1
⇒c=24
a
1
=
4
1
−
24
1
⇒a=
5
24
b
1
=
2
1
−
4
1
⇒b=
7
24
5a+7b+c=24+24+24
=72
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