Math, asked by soniyatharth62, 7 hours ago

If a, b, c and dare four positive real numbers such that abcd = 1, what is the minimum value of (1+a)(1+b)(1+c)(1+d) ?

Answers

Answered by sarishti13052
1

Answer:

16

Step-by-step explanation:

If a, b, c and dare four positive real numbers such that abcd = 1, what is the minimum value of (1+a)(1+b)(1+c)(1+d) ?

Answered by chandanapukalyani
0

Answer:

gvn that abcd =1

abc=1/d

bcd=1/a

acd=1/b

abd=1/c

(1+a)(1+b)(1+c)(1+d)

(1+a+b+ab)(1+c+d+cd)

(1+c+d+cd+a+ac+ad+acd+b+bc+bd+bcd+ab+abc+abd+abcd)

2+a+b+c+d+ab+bc+cd+ac+ad+bd+1/a+1/b+1/c+1/d

naku intha varake vachindhi

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