if A,B,C
angles in
are
ΔABC
α
1
stin A-1 (2-1).infc-1) -
Then
2/2
TanA.TanB =
AΣTanA
(c) (ΣTanA)
(6) ΣCotA
(d) (ΣCotA)
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Answer:
that question is wrong
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