Question

if a,b,c are 3 zeroes of p(x)=6x^3x^2-5x+1, find the values of (i)a+b+c and (ii)a.b.c​

Answer 1

Answer:

(i) -1/6 or 1/6......(According to the Question)

(ii) -1/6

Step-by-step explanation:

If your Question is

6x³ + x² - 5x + 1 = 0

ax³ + bx² + cx + d = 0

where a = 6, b = 1, c = -5, d = 1

Given the zeroes are a, b, and c

Then,

We know that,

(i) Sum of Zeroes = -b/a

a + b + c = -1/6

(ii) Similarly,

Product of zeroes = -d/a

a.b.c = -1/6

If your Question is

6x³ - x² - 5x + 1 = 0

ax³ + bx² + cx + d = 0

where a = 6, b = -1, c = -5, d = 1

Given the zeroes are a, b, and c

Then,

We know that,

(i) Sum of Zeroes = -b/a

a + b + c = -(-1)/6 = 1/6

(ii) Similarly,

Product of zeroes = -d/a

a.b.c = -1/6

Hope you understood it........All the best