Math, asked by nikitajha400, 1 year ago

If a ,b,c are all non zero and a+b+c=0 prove that (a^2/bc)+(b^2/ac)+(c^2/ab)

Answers

Answered by snehitha2
26
Your question might be as follows:-

If a ,b,c are all non zero and a+b+c=0 prove that (a^2/bc)+(b^2/ac)+(c^2/ab) = 3

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Already we know that,

If a+b+c = 0 then a³+b³+c³ = 3abc

→ (a²/bc)+(b²/ac)+(c²/ab)

LCM is abc

→ (a³+b³+c³)/abc

→ 3abc/abc

→ 3

Hence proved!!

Hope it helps...
Answered by Anonymous
1

Answer:

Given- a, b, c are all non zero and a+b+c=0

To prove= a^2/bc+b^2/ca+c^2/ab=3

Proof:

LHS- a^2/bc+b^2/ca+c^2/ab

LCM of bc, ca,and=ABC

=a^3+b^3+c^3/ABC

=3ABC/ABC

=3

[given a+b+c=0 and if a+b+c=0 then a^3+b^3+c^3=3abc]

Mark it as brainliest.....

Step-by-step explanation:

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