If a ,b,c are all non zero and a+b+c=0 prove that (a^2/bc)+(b^2/ac)+(c^2/ab)
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Your question might be as follows:-
If a ,b,c are all non zero and a+b+c=0 prove that (a^2/bc)+(b^2/ac)+(c^2/ab) = 3
==================================
Already we know that,
If a+b+c = 0 then a³+b³+c³ = 3abc
→ (a²/bc)+(b²/ac)+(c²/ab)
LCM is abc
→ (a³+b³+c³)/abc
→ 3abc/abc
→ 3
Hence proved!!
Hope it helps...
If a ,b,c are all non zero and a+b+c=0 prove that (a^2/bc)+(b^2/ac)+(c^2/ab) = 3
==================================
Already we know that,
If a+b+c = 0 then a³+b³+c³ = 3abc
→ (a²/bc)+(b²/ac)+(c²/ab)
LCM is abc
→ (a³+b³+c³)/abc
→ 3abc/abc
→ 3
Hence proved!!
Hope it helps...
Answered by
1
Answer:
Given- a, b, c are all non zero and a+b+c=0
To prove= a^2/bc+b^2/ca+c^2/ab=3
Proof:
LHS- a^2/bc+b^2/ca+c^2/ab
LCM of bc, ca,and=ABC
=a^3+b^3+c^3/ABC
=3ABC/ABC
=3
[given a+b+c=0 and if a+b+c=0 then a^3+b^3+c^3=3abc]
Mark it as brainliest.....
Step-by-step explanation:
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