Math, asked by harshaverma2004, 1 year ago

if a, b, c are all non zero and a+b+c=0. prove that a^2/bc + b^2/ca + c^2/ab = 3
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Answers

Answered by RabbitPanda
3
We know that if a+b+c =0 , then a3 + b3 + c3 = 3abc Now, we have:LHS = a2/bc+b2/ca+c2/ab= a3+b3+c3/abc= 3abc/abc= 3 = RHSHence, proved
Answered by zakir7581p0visq
1
Please mark my answer as brainlest 
We know that a³+b³+c³ = 3abc if a+b+c=0
When we divide 
a³,b³,c³ by abc we get
a²/bc + b²/ca + c²/ab = 3 hence proved

zakir7581p0visq: mark my answer as brainlest
harshaverma2004: thanks for answering
harshaverma2004: in which school you are
zakir7581p0visq: thank you
zakir7581p0visq: kendriya vidyalaya raebareli u.p.
harshaverma2004: ur wlcm
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