Question

If a,b,c are all non zero and a+b+c =0,prove that a3 +b3+c3=3abc by using property ,without actually calculating the cubes ,evaluate (9.8)3-(11.3)3+(1.5)3

Answer 1

here a+b+c=0
then a3+b3+c3=3abc
3×9.8×11.3×1.5=498.33

Answer 2

hope this helps you......