Math, asked by aaiza21, 1 year ago

if a b c are all non zero and a + b + C is equal to zero prove that a square by BC + b square by CA + c square by a b is equal to 3

Answers

Answered by Anonymous
6
If a+b+c=0

then a3+b3+c3=3abc

a2/bc + b2/ca + c2/ab = 3

LCM of bc , ca , ab = abc

a3 + b3 + c3 / abc = 3

3abc / abc = 3

3 = 3

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