if a b c are all non zero and a + b + C is equal to zero prove that a square by BC + b square by CA + c square by a b is equal to 3
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If a+b+c=0
then a3+b3+c3=3abc
a2/bc + b2/ca + c2/ab = 3
LCM of bc , ca , ab = abc
a3 + b3 + c3 / abc = 3
3abc / abc = 3
3 = 3
please mark as BRAINliest answer
then a3+b3+c3=3abc
a2/bc + b2/ca + c2/ab = 3
LCM of bc , ca , ab = abc
a3 + b3 + c3 / abc = 3
3abc / abc = 3
3 = 3
please mark as BRAINliest answer
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