if a,b,c are all non zero anda+b+c=0,prove that a²/bc +b²/ca+c²/ab=3
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If a+b+c=0, then prove that a^2/bc+b^2/ac+c^2/ab=3?
Originally Answered: If a+b+c=0, then prove that a^2/bc+b^2/ab+c^2/CA=3?
by definition of symmetric function, the correct question is a + b + c = 0 => a²/bc + b²/ca + c²/ab.
(a³ + b³ + c³)/abc ={(a + b + c)(a² + b² + c² - ab - bc - ca) + 3abc/abc = 3abc/abc = 3.
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