Math, asked by adthegreat80, 1 year ago

If a,b,c are all non- zero number and a+b+c =0 .Prove that a²/bc+ b²/ca+ c²/ab =3

Answers

Answered by Anonymous
0
use the formula a^3 + b^3 + c^3 = 3abc  

then divide lhs and rhs by abc 
Answered by Anonymous
3

Answer

Let's simplify the given equation first:

 \frac{ {a}^{2} }{bc}  +  \frac{ {b}^{2} }{ca}  +  \frac{ {c}^{2} }{ab}  \\  \\  =  >  \frac{ {a}^{3}  +  {b}^{3}  +  {c}^{3} }{abc}

We know an identity:

When: a + b + c = 0;

 {a}^{3} +   {b}^{3} +   {c}^{3}  = 3abc

Applying the same here:

\frac{ {a}^{3}  +  {b}^{3}  +  {c}^{3} }{abc}   \\  \\  =  >  \frac{3abc}{abc}  \\  \\  =  > 3

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