Question

If a,b,c are all nonzero real numbersand a+b+c=0then prove that a²/bc +b²/ac +c²/ab=3

Answer 1

Answer:

explanation down there

Step-by-step explanation:

since a+b+c=0

a³+b³+c³/abc =3

can be writen as:

$\frac{a^3}{abc}$ + $\frac{b^3}{abc}$ + $\frac{c^3}{abc}$ =3

then, we get that

a²/bc +b²/ac +c²/ab=3