Question

if A,B,C are angles of a traingle and none of them equal to π/2,then prove that tan A+tan B+tanC=tan A Tan B tan C. (answer only if you the know answer)​

Answer 1

Answer:

∵ A, B and C are the angles of a triangle

∴A+B+C=π

∴tan(A+B+C)=tanπ=0

tanA+tanB+tanC−tanAtanBtanC/ 1-tanA tanB-tanB tanC- tanC tanA= 0

tanA+tanB+tanC=tanAtanBtanC