Question

If A,B,C are angles of a triangle and none of them is equal to
then prove that
2
tanA + tanB + tanC = tan A. tanB. tanC.

Answer 1

Answer:

Given: tanA+tanB+tanC=tanAtanBtanC

⇒tanA+tanB=tanAtanBtanC−tanC

⇒tanA+tanB=tanC(tanAtanB−1)

⇒

1−tanAtanB

tanA+tanB

=−tanC

⇒tan(A+B)=−tanC

⇒A+B=−C⇒A+B+C=0

or some integral multiple of π

Step-by-step explanation:

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Answer 2

Answer:

integral multiplication of pir