if A B C are angles of a triangle then prove sin (A+B)= sin C
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Answered by
8
Good Morning!
Angle A + Alngle B + Angle C = 180
A + B = 180 - C
Taking Sin on both sides we have
Sin ( A + B ) = Sin ( 180 - C )
Sin ( A + B ) = Sin C
Becoz Sin ( 180 - x ) = Sin x
Answered by
7
We know that, in a triangle:-
A + B + C = 180°
A + B = 180 - C - - - - - - - - (1)
Now,
Sin ( A + B) = Sin (180 - C) [from eqn 1]
We know that,
Sin (180 - x) = Sin x
Therefore,
Sin(180 - C)= Sin C
So,
Sin (A+B) = Sin C
Hence proved.
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