Question

If a, b, c are any three consecutive integers, prove that
log(1 + ac) = 2 log b
​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

a = n -1   b= n  c = n+1   be three consecutive integers,

ac = [n-1][n+1] =n^2  -  1

1 +ac = n^2

now   log(1 + ac)  =log [n^2] =2log n = 2log b