If a, b, c are distinct integers such that (x-a)(x-b)(x-c)(x-d)=4 has an integer solution x=r. Find the ratio of (a+b+c+d)/r
Answers
Answer:
the answer's 4
Given :- If a, b, c and d are distinct integers such that (x-a)(x-b)(x-c)(x-d) = 4 has an integer solution x = r.
To Find :-
- The ratio of (a+b+c+d)/r = ?
Solution :-
→ (x - a) * (x - b) * (x - c) * (x - d) = 4
since a,b,c and d distinct integers ,
→ (x - a) * (x - b) * (x - c) * (x - d) = 1 * (-1) * 2 * (-2) [ note here
we can write 1 * (-1) * (-2) * 2 or 2 * 1 * (-2) * (-1) , all have same values .]
comparing we get,
→ x - a = 1 => a = (x - 1)
→ x - b = (-1) => b = (x + 1)
→ x - c = 2 => c = x - 2
→ x - d = (-2) => d = x + 2 .
then,
→ (a + b + c + d)/r
→ (x - 1 + x + 1 + x - 2 + x + 2)/r
→ 4x/r
given that x = r,
therefore,
→ 4r/r
→ 4 .
Hence, the ratio of (a+b+c+d)/r will be (4/1) or we can say that (a + b + c + d) : r = 4 : 1 .
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